MAYBE
proof of input_lRp6Pz7aEP.trs
# AProVE Commit ID: aff8ecad908e01718a4c36e68d2e55d5e0f16e15 fuhs 20220216 unpublished


The Runtime Complexity (parallel-innermost) of the given CpxTRS could be proven to be BOUNDS(1, INF).

(0) CpxTRS
(1) RenamingProof [BOTH BOUNDS(ID, ID), 0 ms]
(2) CpxTRS
(3) RelTrsToTrsProof [UPPER BOUND(ID), 0 ms]
(4) CpxTRS
(5) RelTrsToWeightedTrsProof [UPPER BOUND(ID), 0 ms]
(6) CpxWeightedTrs
    (7) TypeInferenceProof [BOTH BOUNDS(ID, ID), 0 ms]
    (8) CpxTypedWeightedTrs
    (9) CompletionProof [UPPER BOUND(ID), 0 ms]
    (10) CpxTypedWeightedCompleteTrs
        (11) NarrowingProof [BOTH BOUNDS(ID, ID), 0 ms]
        (12) CpxTypedWeightedCompleteTrs
        (13) CpxTypedWeightedTrsToRntsProof [UPPER BOUND(ID), 0 ms]
        (14) CpxRNTS
        (15) SimplificationProof [BOTH BOUNDS(ID, ID), 0 ms]
        (16) CpxRNTS
        (17) CpxRntsAnalysisOrderProof [BOTH BOUNDS(ID, ID), 0 ms]
        (18) CpxRNTS
        (19) ResultPropagationProof [UPPER BOUND(ID), 1 ms]
        (20) CpxRNTS
        (21) IntTrsBoundProof [UPPER BOUND(ID), 149 ms]
        (22) CpxRNTS
        (23) IntTrsBoundProof [UPPER BOUND(ID), 59 ms]
        (24) CpxRNTS
        (25) ResultPropagationProof [UPPER BOUND(ID), 0 ms]
        (26) CpxRNTS
        (27) IntTrsBoundProof [UPPER BOUND(ID), 912 ms]
        (28) CpxRNTS
        (29) IntTrsBoundProof [UPPER BOUND(ID), 165 ms]
        (30) CpxRNTS
    (31) CompletionProof [UPPER BOUND(ID), 0 ms]
    (32) CpxTypedWeightedCompleteTrs
        (33) CpxTypedWeightedTrsToRntsProof [UPPER BOUND(ID), 0 ms]
        (34) CpxRNTS
(35) CpxTrsToCdtProof [UPPER BOUND(ID), 0 ms]
(36) CdtProblem
    (37) CdtLeafRemovalProof [BOTH BOUNDS(ID, ID), 0 ms]
    (38) CdtProblem
    (39) CdtUsableRulesProof [BOTH BOUNDS(ID, ID), 0 ms]
    (40) CdtProblem
    (41) CdtRuleRemovalProof [UPPER BOUND(ADD(n^1)), 58 ms]
    (42) CdtProblem
    (43) CdtRuleRemovalProof [UPPER BOUND(ADD(n^1)), 9 ms]
    (44) CdtProblem
    (45) CdtRuleRemovalProof [UPPER BOUND(ADD(n^1)), 0 ms]
    (46) CdtProblem
    (47) CdtForwardInstantiationProof [BOTH BOUNDS(ID, ID), 0 ms]
    (48) CdtProblem
    (49) CdtInstantiationProof [BOTH BOUNDS(ID, ID), 0 ms]
    (50) CdtProblem
    (51) CdtInstantiationProof [BOTH BOUNDS(ID, ID), 0 ms]
    (52) CdtProblem
    (53) CdtForwardInstantiationProof [BOTH BOUNDS(ID, ID), 0 ms]
    (54) CdtProblem
    (55) CdtForwardInstantiationProof [BOTH BOUNDS(ID, ID), 0 ms]
    (56) CdtProblem
    (57) CdtForwardInstantiationProof [BOTH BOUNDS(ID, ID), 0 ms]
    (58) CdtProblem
    (59) CdtForwardInstantiationProof [BOTH BOUNDS(ID, ID), 0 ms]
    (60) CdtProblem
    (61) CdtForwardInstantiationProof [BOTH BOUNDS(ID, ID), 0 ms]
    (62) CdtProblem


----------------------------------------

(0)
Obligation:
The Runtime Complexity (parallel-innermost) of the given CpxTRS could be proven to be BOUNDS(1, INF).


The TRS R consists of the following rules:

   fst(0, Z) -> nil
   fst(s(X), cons(Y, Z)) -> cons(Y, fst(X, Z))
   from(X) -> cons(X, from(s(X)))
   add(0, X) -> X
   add(s(X), Y) -> s(add(X, Y))
   len(nil) -> 0
   len(cons(X, Z)) -> s(len(Z))

S is empty.
Rewrite Strategy: PARALLEL_INNERMOST
----------------------------------------

(1) RenamingProof (BOTH BOUNDS(ID, ID))
Renamed function symbols to avoid clashes with predefined symbol.
----------------------------------------

(2)
Obligation:
The Runtime Complexity (parallel-innermost) of the given CpxTRS could be proven to be BOUNDS(1, INF).


The TRS R consists of the following rules:

   fst(0', Z) -> nil
   fst(s(X), cons(Y, Z)) -> cons(Y, fst(X, Z))
   from(X) -> cons(X, from(s(X)))
   add(0', X) -> X
   add(s(X), Y) -> s(add(X, Y))
   len(nil) -> 0'
   len(cons(X, Z)) -> s(len(Z))

S is empty.
Rewrite Strategy: PARALLEL_INNERMOST
----------------------------------------

(3) RelTrsToTrsProof (UPPER BOUND(ID))
transformed relative TRS to TRS
----------------------------------------

(4)
Obligation:
The Runtime Complexity (parallel-innermost) of the given CpxTRS could be proven to be BOUNDS(1, INF).


The TRS R consists of the following rules:

   fst(0, Z) -> nil
   fst(s(X), cons(Y, Z)) -> cons(Y, fst(X, Z))
   from(X) -> cons(X, from(s(X)))
   add(0, X) -> X
   add(s(X), Y) -> s(add(X, Y))
   len(nil) -> 0
   len(cons(X, Z)) -> s(len(Z))

S is empty.
Rewrite Strategy: PARALLEL_INNERMOST
----------------------------------------

(5) RelTrsToWeightedTrsProof (UPPER BOUND(ID))
Transformed relative TRS to weighted TRS
----------------------------------------

(6)
Obligation:
The Runtime Complexity (innermost) of the given CpxWeightedTrs could be proven to be BOUNDS(1, INF).


The TRS R consists of the following rules:

   fst(0, Z) -> nil [1]
   fst(s(X), cons(Y, Z)) -> cons(Y, fst(X, Z)) [1]
   from(X) -> cons(X, from(s(X))) [1]
   add(0, X) -> X [1]
   add(s(X), Y) -> s(add(X, Y)) [1]
   len(nil) -> 0 [1]
   len(cons(X, Z)) -> s(len(Z)) [1]

Rewrite Strategy: INNERMOST
----------------------------------------

(7) TypeInferenceProof (BOTH BOUNDS(ID, ID))
Infered types.
----------------------------------------

(8)
Obligation:
Runtime Complexity Weighted TRS with Types.
The TRS R consists of the following rules:

   fst(0, Z) -> nil [1]
   fst(s(X), cons(Y, Z)) -> cons(Y, fst(X, Z)) [1]
   from(X) -> cons(X, from(s(X))) [1]
   add(0, X) -> X [1]
   add(s(X), Y) -> s(add(X, Y)) [1]
   len(nil) -> 0 [1]
   len(cons(X, Z)) -> s(len(Z)) [1]

The TRS has the following type information:
fst :: 0:s -> nil:cons -> nil:cons
0 :: 0:s
nil :: nil:cons
s :: 0:s -> 0:s
cons :: 0:s -> nil:cons -> nil:cons
from :: 0:s -> nil:cons
add :: 0:s -> 0:s -> 0:s
len :: nil:cons -> 0:s

Rewrite Strategy: INNERMOST
----------------------------------------

(9) CompletionProof (UPPER BOUND(ID))
The transformation into a RNTS is sound, since:

(a) The obligation is a constructor system where every type has a constant constructor,

(b) The following defined symbols do not have to be completely defined, as they can never occur inside other defined symbols:

   fst_2
   from_1
   add_2
   len_1

(c) The following functions are completely defined:
none

Due to the following rules being added:
none

And the following fresh constants: none

----------------------------------------

(10)
Obligation:
Runtime Complexity Weighted TRS where critical functions are completely defined. The underlying TRS is:

Runtime Complexity Weighted TRS with Types.
The TRS R consists of the following rules:

   fst(0, Z) -> nil [1]
   fst(s(X), cons(Y, Z)) -> cons(Y, fst(X, Z)) [1]
   from(X) -> cons(X, from(s(X))) [1]
   add(0, X) -> X [1]
   add(s(X), Y) -> s(add(X, Y)) [1]
   len(nil) -> 0 [1]
   len(cons(X, Z)) -> s(len(Z)) [1]

The TRS has the following type information:
fst :: 0:s -> nil:cons -> nil:cons
0 :: 0:s
nil :: nil:cons
s :: 0:s -> 0:s
cons :: 0:s -> nil:cons -> nil:cons
from :: 0:s -> nil:cons
add :: 0:s -> 0:s -> 0:s
len :: nil:cons -> 0:s

Rewrite Strategy: INNERMOST
----------------------------------------

(11) NarrowingProof (BOTH BOUNDS(ID, ID))
Narrowed the inner basic terms of all right-hand sides by a single narrowing step.
----------------------------------------

(12)
Obligation:
Runtime Complexity Weighted TRS where critical functions are completely defined. The underlying TRS is:

Runtime Complexity Weighted TRS with Types.
The TRS R consists of the following rules:

   fst(0, Z) -> nil [1]
   fst(s(X), cons(Y, Z)) -> cons(Y, fst(X, Z)) [1]
   from(X) -> cons(X, from(s(X))) [1]
   add(0, X) -> X [1]
   add(s(X), Y) -> s(add(X, Y)) [1]
   len(nil) -> 0 [1]
   len(cons(X, Z)) -> s(len(Z)) [1]

The TRS has the following type information:
fst :: 0:s -> nil:cons -> nil:cons
0 :: 0:s
nil :: nil:cons
s :: 0:s -> 0:s
cons :: 0:s -> nil:cons -> nil:cons
from :: 0:s -> nil:cons
add :: 0:s -> 0:s -> 0:s
len :: nil:cons -> 0:s

Rewrite Strategy: INNERMOST
----------------------------------------

(13) CpxTypedWeightedTrsToRntsProof (UPPER BOUND(ID))
Transformed the TRS into an over-approximating RNTS by (improved) Size Abstraction.
The constant constructors are abstracted as follows:

   0 => 0
   nil => 0

----------------------------------------

(14)
Obligation:
Complexity RNTS consisting of the following rules:

   add(z, z') -{ 1 }-> X :|: z' = X, X >= 0, z = 0
   add(z, z') -{ 1 }-> 1 + add(X, Y) :|: z = 1 + X, z' = Y, Y >= 0, X >= 0
   from(z) -{ 1 }-> 1 + X + from(1 + X) :|: X >= 0, z = X
   fst(z, z') -{ 1 }-> 0 :|: Z >= 0, z' = Z, z = 0
   fst(z, z') -{ 1 }-> 1 + Y + fst(X, Z) :|: Z >= 0, z = 1 + X, Y >= 0, X >= 0, z' = 1 + Y + Z
   len(z) -{ 1 }-> 0 :|: z = 0
   len(z) -{ 1 }-> 1 + len(Z) :|: Z >= 0, X >= 0, z = 1 + X + Z


----------------------------------------

(15) SimplificationProof (BOTH BOUNDS(ID, ID))
Simplified the RNTS by moving equalities from the constraints into the right-hand sides.
----------------------------------------

(16)
Obligation:
Complexity RNTS consisting of the following rules:

   add(z, z') -{ 1 }-> z' :|: z' >= 0, z = 0
   add(z, z') -{ 1 }-> 1 + add(z - 1, z') :|: z' >= 0, z - 1 >= 0
   from(z) -{ 1 }-> 1 + z + from(1 + z) :|: z >= 0
   fst(z, z') -{ 1 }-> 0 :|: z' >= 0, z = 0
   fst(z, z') -{ 1 }-> 1 + Y + fst(z - 1, Z) :|: Z >= 0, Y >= 0, z - 1 >= 0, z' = 1 + Y + Z
   len(z) -{ 1 }-> 0 :|: z = 0
   len(z) -{ 1 }-> 1 + len(Z) :|: Z >= 0, X >= 0, z = 1 + X + Z


----------------------------------------

(17) CpxRntsAnalysisOrderProof (BOTH BOUNDS(ID, ID))
Found the following analysis order by SCC decomposition:

   { len }
   { from }
   { add }
   { fst }

----------------------------------------

(18)
Obligation:
Complexity RNTS consisting of the following rules:

   add(z, z') -{ 1 }-> z' :|: z' >= 0, z = 0
   add(z, z') -{ 1 }-> 1 + add(z - 1, z') :|: z' >= 0, z - 1 >= 0
   from(z) -{ 1 }-> 1 + z + from(1 + z) :|: z >= 0
   fst(z, z') -{ 1 }-> 0 :|: z' >= 0, z = 0
   fst(z, z') -{ 1 }-> 1 + Y + fst(z - 1, Z) :|: Z >= 0, Y >= 0, z - 1 >= 0, z' = 1 + Y + Z
   len(z) -{ 1 }-> 0 :|: z = 0
   len(z) -{ 1 }-> 1 + len(Z) :|: Z >= 0, X >= 0, z = 1 + X + Z

Function symbols to be analyzed: {len}, {from}, {add}, {fst}

----------------------------------------

(19) ResultPropagationProof (UPPER BOUND(ID))
Applied inner abstraction using the recently inferred runtime/size bounds where possible.
----------------------------------------

(20)
Obligation:
Complexity RNTS consisting of the following rules:

   add(z, z') -{ 1 }-> z' :|: z' >= 0, z = 0
   add(z, z') -{ 1 }-> 1 + add(z - 1, z') :|: z' >= 0, z - 1 >= 0
   from(z) -{ 1 }-> 1 + z + from(1 + z) :|: z >= 0
   fst(z, z') -{ 1 }-> 0 :|: z' >= 0, z = 0
   fst(z, z') -{ 1 }-> 1 + Y + fst(z - 1, Z) :|: Z >= 0, Y >= 0, z - 1 >= 0, z' = 1 + Y + Z
   len(z) -{ 1 }-> 0 :|: z = 0
   len(z) -{ 1 }-> 1 + len(Z) :|: Z >= 0, X >= 0, z = 1 + X + Z

Function symbols to be analyzed: {len}, {from}, {add}, {fst}

----------------------------------------

(21) IntTrsBoundProof (UPPER BOUND(ID))

Computed SIZE bound using CoFloCo for: len
after applying outer abstraction to obtain an ITS,
resulting in: O(n^1) with polynomial bound: z

----------------------------------------

(22)
Obligation:
Complexity RNTS consisting of the following rules:

   add(z, z') -{ 1 }-> z' :|: z' >= 0, z = 0
   add(z, z') -{ 1 }-> 1 + add(z - 1, z') :|: z' >= 0, z - 1 >= 0
   from(z) -{ 1 }-> 1 + z + from(1 + z) :|: z >= 0
   fst(z, z') -{ 1 }-> 0 :|: z' >= 0, z = 0
   fst(z, z') -{ 1 }-> 1 + Y + fst(z - 1, Z) :|: Z >= 0, Y >= 0, z - 1 >= 0, z' = 1 + Y + Z
   len(z) -{ 1 }-> 0 :|: z = 0
   len(z) -{ 1 }-> 1 + len(Z) :|: Z >= 0, X >= 0, z = 1 + X + Z

Function symbols to be analyzed: {len}, {from}, {add}, {fst}
Previous analysis results are:
  len: runtime: ?, size: O(n^1) [z]

----------------------------------------

(23) IntTrsBoundProof (UPPER BOUND(ID))

Computed RUNTIME bound using CoFloCo for: len
after applying outer abstraction to obtain an ITS,
resulting in: O(n^1) with polynomial bound: 1 + z

----------------------------------------

(24)
Obligation:
Complexity RNTS consisting of the following rules:

   add(z, z') -{ 1 }-> z' :|: z' >= 0, z = 0
   add(z, z') -{ 1 }-> 1 + add(z - 1, z') :|: z' >= 0, z - 1 >= 0
   from(z) -{ 1 }-> 1 + z + from(1 + z) :|: z >= 0
   fst(z, z') -{ 1 }-> 0 :|: z' >= 0, z = 0
   fst(z, z') -{ 1 }-> 1 + Y + fst(z - 1, Z) :|: Z >= 0, Y >= 0, z - 1 >= 0, z' = 1 + Y + Z
   len(z) -{ 1 }-> 0 :|: z = 0
   len(z) -{ 1 }-> 1 + len(Z) :|: Z >= 0, X >= 0, z = 1 + X + Z

Function symbols to be analyzed: {from}, {add}, {fst}
Previous analysis results are:
  len: runtime: O(n^1) [1 + z], size: O(n^1) [z]

----------------------------------------

(25) ResultPropagationProof (UPPER BOUND(ID))
Applied inner abstraction using the recently inferred runtime/size bounds where possible.
----------------------------------------

(26)
Obligation:
Complexity RNTS consisting of the following rules:

   add(z, z') -{ 1 }-> z' :|: z' >= 0, z = 0
   add(z, z') -{ 1 }-> 1 + add(z - 1, z') :|: z' >= 0, z - 1 >= 0
   from(z) -{ 1 }-> 1 + z + from(1 + z) :|: z >= 0
   fst(z, z') -{ 1 }-> 0 :|: z' >= 0, z = 0
   fst(z, z') -{ 1 }-> 1 + Y + fst(z - 1, Z) :|: Z >= 0, Y >= 0, z - 1 >= 0, z' = 1 + Y + Z
   len(z) -{ 1 }-> 0 :|: z = 0
   len(z) -{ 2 + Z }-> 1 + s :|: s >= 0, s <= Z, Z >= 0, X >= 0, z = 1 + X + Z

Function symbols to be analyzed: {from}, {add}, {fst}
Previous analysis results are:
  len: runtime: O(n^1) [1 + z], size: O(n^1) [z]

----------------------------------------

(27) IntTrsBoundProof (UPPER BOUND(ID))

Computed SIZE bound using CoFloCo for: from
after applying outer abstraction to obtain an ITS,
resulting in: O(1) with polynomial bound: 0

----------------------------------------

(28)
Obligation:
Complexity RNTS consisting of the following rules:

   add(z, z') -{ 1 }-> z' :|: z' >= 0, z = 0
   add(z, z') -{ 1 }-> 1 + add(z - 1, z') :|: z' >= 0, z - 1 >= 0
   from(z) -{ 1 }-> 1 + z + from(1 + z) :|: z >= 0
   fst(z, z') -{ 1 }-> 0 :|: z' >= 0, z = 0
   fst(z, z') -{ 1 }-> 1 + Y + fst(z - 1, Z) :|: Z >= 0, Y >= 0, z - 1 >= 0, z' = 1 + Y + Z
   len(z) -{ 1 }-> 0 :|: z = 0
   len(z) -{ 2 + Z }-> 1 + s :|: s >= 0, s <= Z, Z >= 0, X >= 0, z = 1 + X + Z

Function symbols to be analyzed: {from}, {add}, {fst}
Previous analysis results are:
  len: runtime: O(n^1) [1 + z], size: O(n^1) [z]
  from: runtime: ?, size: O(1) [0]

----------------------------------------

(29) IntTrsBoundProof (UPPER BOUND(ID))

Computed RUNTIME bound using CoFloCo for: from
after applying outer abstraction to obtain an ITS,
resulting in: INF with polynomial bound: ?

----------------------------------------

(30)
Obligation:
Complexity RNTS consisting of the following rules:

   add(z, z') -{ 1 }-> z' :|: z' >= 0, z = 0
   add(z, z') -{ 1 }-> 1 + add(z - 1, z') :|: z' >= 0, z - 1 >= 0
   from(z) -{ 1 }-> 1 + z + from(1 + z) :|: z >= 0
   fst(z, z') -{ 1 }-> 0 :|: z' >= 0, z = 0
   fst(z, z') -{ 1 }-> 1 + Y + fst(z - 1, Z) :|: Z >= 0, Y >= 0, z - 1 >= 0, z' = 1 + Y + Z
   len(z) -{ 1 }-> 0 :|: z = 0
   len(z) -{ 2 + Z }-> 1 + s :|: s >= 0, s <= Z, Z >= 0, X >= 0, z = 1 + X + Z

Function symbols to be analyzed: {from}, {add}, {fst}
Previous analysis results are:
  len: runtime: O(n^1) [1 + z], size: O(n^1) [z]
  from: runtime: INF, size: O(1) [0]

----------------------------------------

(31) CompletionProof (UPPER BOUND(ID))
The TRS is a completely defined constructor system, as every type has a constant constructor and the following rules were added:

   fst(v0, v1) -> null_fst [0]
   len(v0) -> null_len [0]
   add(v0, v1) -> null_add [0]

And the following fresh constants:    null_fst, null_len, null_add

----------------------------------------

(32)
Obligation:
Runtime Complexity Weighted TRS where all functions are completely defined. The underlying TRS is:

Runtime Complexity Weighted TRS with Types.
The TRS R consists of the following rules:

   fst(0, Z) -> nil [1]
   fst(s(X), cons(Y, Z)) -> cons(Y, fst(X, Z)) [1]
   from(X) -> cons(X, from(s(X))) [1]
   add(0, X) -> X [1]
   add(s(X), Y) -> s(add(X, Y)) [1]
   len(nil) -> 0 [1]
   len(cons(X, Z)) -> s(len(Z)) [1]
   fst(v0, v1) -> null_fst [0]
   len(v0) -> null_len [0]
   add(v0, v1) -> null_add [0]

The TRS has the following type information:
fst :: 0:s:null_len:null_add -> nil:cons:null_fst -> nil:cons:null_fst
0 :: 0:s:null_len:null_add
nil :: nil:cons:null_fst
s :: 0:s:null_len:null_add -> 0:s:null_len:null_add
cons :: 0:s:null_len:null_add -> nil:cons:null_fst -> nil:cons:null_fst
from :: 0:s:null_len:null_add -> nil:cons:null_fst
add :: 0:s:null_len:null_add -> 0:s:null_len:null_add -> 0:s:null_len:null_add
len :: nil:cons:null_fst -> 0:s:null_len:null_add
null_fst :: nil:cons:null_fst
null_len :: 0:s:null_len:null_add
null_add :: 0:s:null_len:null_add

Rewrite Strategy: INNERMOST
----------------------------------------

(33) CpxTypedWeightedTrsToRntsProof (UPPER BOUND(ID))
Transformed the TRS into an over-approximating RNTS by (improved) Size Abstraction.
The constant constructors are abstracted as follows:

   0 => 0
   nil => 0
   null_fst => 0
   null_len => 0
   null_add => 0

----------------------------------------

(34)
Obligation:
Complexity RNTS consisting of the following rules:

   add(z, z') -{ 1 }-> X :|: z' = X, X >= 0, z = 0
   add(z, z') -{ 0 }-> 0 :|: v0 >= 0, v1 >= 0, z = v0, z' = v1
   add(z, z') -{ 1 }-> 1 + add(X, Y) :|: z = 1 + X, z' = Y, Y >= 0, X >= 0
   from(z) -{ 1 }-> 1 + X + from(1 + X) :|: X >= 0, z = X
   fst(z, z') -{ 1 }-> 0 :|: Z >= 0, z' = Z, z = 0
   fst(z, z') -{ 0 }-> 0 :|: v0 >= 0, v1 >= 0, z = v0, z' = v1
   fst(z, z') -{ 1 }-> 1 + Y + fst(X, Z) :|: Z >= 0, z = 1 + X, Y >= 0, X >= 0, z' = 1 + Y + Z
   len(z) -{ 1 }-> 0 :|: z = 0
   len(z) -{ 0 }-> 0 :|: v0 >= 0, z = v0
   len(z) -{ 1 }-> 1 + len(Z) :|: Z >= 0, X >= 0, z = 1 + X + Z

Only complete derivations are relevant for the runtime complexity.

----------------------------------------

(35) CpxTrsToCdtProof (UPPER BOUND(ID))
Converted Cpx (relative) TRS with rewrite strategy PARALLEL_INNERMOST to CDT
----------------------------------------

(36)
Obligation:
Complexity Dependency Tuples Problem

Rules:
   fst(0, z0) -> nil
   fst(s(z0), cons(z1, z2)) -> cons(z1, fst(z0, z2))
   from(z0) -> cons(z0, from(s(z0)))
   add(0, z0) -> z0
   add(s(z0), z1) -> s(add(z0, z1))
   len(nil) -> 0
   len(cons(z0, z1)) -> s(len(z1))
Tuples:
   FST(0, z0) -> c
   FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2))
   FROM(z0) -> c2(FROM(s(z0)))
   ADD(0, z0) -> c3
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   LEN(nil) -> c5
   LEN(cons(z0, z1)) -> c6(LEN(z1))
S tuples:
   FST(0, z0) -> c
   FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2))
   FROM(z0) -> c2(FROM(s(z0)))
   ADD(0, z0) -> c3
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   LEN(nil) -> c5
   LEN(cons(z0, z1)) -> c6(LEN(z1))
K tuples:none
Defined Rule Symbols:   fst_2, from_1, add_2, len_1

Defined Pair Symbols:   FST_2, FROM_1, ADD_2, LEN_1

Compound Symbols:   c, c1_1, c2_1, c3, c4_1, c5, c6_1


----------------------------------------

(37) CdtLeafRemovalProof (BOTH BOUNDS(ID, ID))
Removed 3 trailing nodes:
   ADD(0, z0) -> c3
   FST(0, z0) -> c
   LEN(nil) -> c5

----------------------------------------

(38)
Obligation:
Complexity Dependency Tuples Problem

Rules:
   fst(0, z0) -> nil
   fst(s(z0), cons(z1, z2)) -> cons(z1, fst(z0, z2))
   from(z0) -> cons(z0, from(s(z0)))
   add(0, z0) -> z0
   add(s(z0), z1) -> s(add(z0, z1))
   len(nil) -> 0
   len(cons(z0, z1)) -> s(len(z1))
Tuples:
   FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2))
   FROM(z0) -> c2(FROM(s(z0)))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   LEN(cons(z0, z1)) -> c6(LEN(z1))
S tuples:
   FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2))
   FROM(z0) -> c2(FROM(s(z0)))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   LEN(cons(z0, z1)) -> c6(LEN(z1))
K tuples:none
Defined Rule Symbols:   fst_2, from_1, add_2, len_1

Defined Pair Symbols:   FST_2, FROM_1, ADD_2, LEN_1

Compound Symbols:   c1_1, c2_1, c4_1, c6_1


----------------------------------------

(39) CdtUsableRulesProof (BOTH BOUNDS(ID, ID))
The following rules are not usable and were removed:
   fst(0, z0) -> nil
   fst(s(z0), cons(z1, z2)) -> cons(z1, fst(z0, z2))
   from(z0) -> cons(z0, from(s(z0)))
   add(0, z0) -> z0
   add(s(z0), z1) -> s(add(z0, z1))
   len(nil) -> 0
   len(cons(z0, z1)) -> s(len(z1))

----------------------------------------

(40)
Obligation:
Complexity Dependency Tuples Problem

Rules:none
Tuples:
   FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2))
   FROM(z0) -> c2(FROM(s(z0)))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   LEN(cons(z0, z1)) -> c6(LEN(z1))
S tuples:
   FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2))
   FROM(z0) -> c2(FROM(s(z0)))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   LEN(cons(z0, z1)) -> c6(LEN(z1))
K tuples:none
Defined Rule Symbols:none

Defined Pair Symbols:   FST_2, FROM_1, ADD_2, LEN_1

Compound Symbols:   c1_1, c2_1, c4_1, c6_1


----------------------------------------

(41) CdtRuleRemovalProof (UPPER BOUND(ADD(n^1)))
Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.
   FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2))
We considered the (Usable) Rules:none
And the Tuples:
   FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2))
   FROM(z0) -> c2(FROM(s(z0)))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   LEN(cons(z0, z1)) -> c6(LEN(z1))
The order we found is given by the following interpretation:

Polynomial interpretation :

   POL(ADD(x_1, x_2)) = 0
   POL(FROM(x_1)) = 0
   POL(FST(x_1, x_2)) = x_1 + x_2
   POL(LEN(x_1)) = x_1
   POL(c1(x_1)) = x_1
   POL(c2(x_1)) = x_1
   POL(c4(x_1)) = x_1
   POL(c6(x_1)) = x_1
   POL(cons(x_1, x_2)) = x_2
   POL(s(x_1)) = [1] + x_1

----------------------------------------

(42)
Obligation:
Complexity Dependency Tuples Problem

Rules:none
Tuples:
   FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2))
   FROM(z0) -> c2(FROM(s(z0)))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   LEN(cons(z0, z1)) -> c6(LEN(z1))
S tuples:
   FROM(z0) -> c2(FROM(s(z0)))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   LEN(cons(z0, z1)) -> c6(LEN(z1))
K tuples:
   FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2))
Defined Rule Symbols:none

Defined Pair Symbols:   FST_2, FROM_1, ADD_2, LEN_1

Compound Symbols:   c1_1, c2_1, c4_1, c6_1


----------------------------------------

(43) CdtRuleRemovalProof (UPPER BOUND(ADD(n^1)))
Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.
   LEN(cons(z0, z1)) -> c6(LEN(z1))
We considered the (Usable) Rules:none
And the Tuples:
   FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2))
   FROM(z0) -> c2(FROM(s(z0)))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   LEN(cons(z0, z1)) -> c6(LEN(z1))
The order we found is given by the following interpretation:

Polynomial interpretation :

   POL(ADD(x_1, x_2)) = x_1
   POL(FROM(x_1)) = x_1
   POL(FST(x_1, x_2)) = x_1 + x_2
   POL(LEN(x_1)) = x_1
   POL(c1(x_1)) = x_1
   POL(c2(x_1)) = x_1
   POL(c4(x_1)) = x_1
   POL(c6(x_1)) = x_1
   POL(cons(x_1, x_2)) = [1] + x_2
   POL(s(x_1)) = x_1

----------------------------------------

(44)
Obligation:
Complexity Dependency Tuples Problem

Rules:none
Tuples:
   FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2))
   FROM(z0) -> c2(FROM(s(z0)))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   LEN(cons(z0, z1)) -> c6(LEN(z1))
S tuples:
   FROM(z0) -> c2(FROM(s(z0)))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
K tuples:
   FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2))
   LEN(cons(z0, z1)) -> c6(LEN(z1))
Defined Rule Symbols:none

Defined Pair Symbols:   FST_2, FROM_1, ADD_2, LEN_1

Compound Symbols:   c1_1, c2_1, c4_1, c6_1


----------------------------------------

(45) CdtRuleRemovalProof (UPPER BOUND(ADD(n^1)))
Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
We considered the (Usable) Rules:none
And the Tuples:
   FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2))
   FROM(z0) -> c2(FROM(s(z0)))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   LEN(cons(z0, z1)) -> c6(LEN(z1))
The order we found is given by the following interpretation:

Polynomial interpretation :

   POL(ADD(x_1, x_2)) = x_1
   POL(FROM(x_1)) = 0
   POL(FST(x_1, x_2)) = x_2
   POL(LEN(x_1)) = x_1
   POL(c1(x_1)) = x_1
   POL(c2(x_1)) = x_1
   POL(c4(x_1)) = x_1
   POL(c6(x_1)) = x_1
   POL(cons(x_1, x_2)) = x_2
   POL(s(x_1)) = [1] + x_1

----------------------------------------

(46)
Obligation:
Complexity Dependency Tuples Problem

Rules:none
Tuples:
   FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2))
   FROM(z0) -> c2(FROM(s(z0)))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   LEN(cons(z0, z1)) -> c6(LEN(z1))
S tuples:
   FROM(z0) -> c2(FROM(s(z0)))
K tuples:
   FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2))
   LEN(cons(z0, z1)) -> c6(LEN(z1))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
Defined Rule Symbols:none

Defined Pair Symbols:   FST_2, FROM_1, ADD_2, LEN_1

Compound Symbols:   c1_1, c2_1, c4_1, c6_1


----------------------------------------

(47) CdtForwardInstantiationProof (BOTH BOUNDS(ID, ID))
Use forward instantiation to replace FST(s(z0), cons(z1, z2)) -> c1(FST(z0, z2)) by 
   FST(s(s(y0)), cons(z1, cons(y1, y2))) -> c1(FST(s(y0), cons(y1, y2)))

----------------------------------------

(48)
Obligation:
Complexity Dependency Tuples Problem

Rules:none
Tuples:
   FROM(z0) -> c2(FROM(s(z0)))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   LEN(cons(z0, z1)) -> c6(LEN(z1))
   FST(s(s(y0)), cons(z1, cons(y1, y2))) -> c1(FST(s(y0), cons(y1, y2)))
S tuples:
   FROM(z0) -> c2(FROM(s(z0)))
K tuples:
   LEN(cons(z0, z1)) -> c6(LEN(z1))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   FST(s(s(y0)), cons(z1, cons(y1, y2))) -> c1(FST(s(y0), cons(y1, y2)))
Defined Rule Symbols:none

Defined Pair Symbols:   FROM_1, ADD_2, LEN_1, FST_2

Compound Symbols:   c2_1, c4_1, c6_1, c1_1


----------------------------------------

(49) CdtInstantiationProof (BOTH BOUNDS(ID, ID))
Use instantiation to replace FROM(z0) -> c2(FROM(s(z0))) by 
   FROM(s(x0)) -> c2(FROM(s(s(x0))))

----------------------------------------

(50)
Obligation:
Complexity Dependency Tuples Problem

Rules:none
Tuples:
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   LEN(cons(z0, z1)) -> c6(LEN(z1))
   FST(s(s(y0)), cons(z1, cons(y1, y2))) -> c1(FST(s(y0), cons(y1, y2)))
   FROM(s(x0)) -> c2(FROM(s(s(x0))))
S tuples:
   FROM(s(x0)) -> c2(FROM(s(s(x0))))
K tuples:
   LEN(cons(z0, z1)) -> c6(LEN(z1))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   FST(s(s(y0)), cons(z1, cons(y1, y2))) -> c1(FST(s(y0), cons(y1, y2)))
Defined Rule Symbols:none

Defined Pair Symbols:   ADD_2, LEN_1, FST_2, FROM_1

Compound Symbols:   c4_1, c6_1, c1_1, c2_1


----------------------------------------

(51) CdtInstantiationProof (BOTH BOUNDS(ID, ID))
Use instantiation to replace FROM(s(x0)) -> c2(FROM(s(s(x0)))) by 
   FROM(s(s(x0))) -> c2(FROM(s(s(s(x0)))))

----------------------------------------

(52)
Obligation:
Complexity Dependency Tuples Problem

Rules:none
Tuples:
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   LEN(cons(z0, z1)) -> c6(LEN(z1))
   FST(s(s(y0)), cons(z1, cons(y1, y2))) -> c1(FST(s(y0), cons(y1, y2)))
   FROM(s(s(x0))) -> c2(FROM(s(s(s(x0)))))
S tuples:
   FROM(s(s(x0))) -> c2(FROM(s(s(s(x0)))))
K tuples:
   LEN(cons(z0, z1)) -> c6(LEN(z1))
   ADD(s(z0), z1) -> c4(ADD(z0, z1))
   FST(s(s(y0)), cons(z1, cons(y1, y2))) -> c1(FST(s(y0), cons(y1, y2)))
Defined Rule Symbols:none

Defined Pair Symbols:   ADD_2, LEN_1, FST_2, FROM_1

Compound Symbols:   c4_1, c6_1, c1_1, c2_1


----------------------------------------

(53) CdtForwardInstantiationProof (BOTH BOUNDS(ID, ID))
Use forward instantiation to replace ADD(s(z0), z1) -> c4(ADD(z0, z1)) by 
   ADD(s(s(y0)), z1) -> c4(ADD(s(y0), z1))

----------------------------------------

(54)
Obligation:
Complexity Dependency Tuples Problem

Rules:none
Tuples:
   LEN(cons(z0, z1)) -> c6(LEN(z1))
   FST(s(s(y0)), cons(z1, cons(y1, y2))) -> c1(FST(s(y0), cons(y1, y2)))
   FROM(s(s(x0))) -> c2(FROM(s(s(s(x0)))))
   ADD(s(s(y0)), z1) -> c4(ADD(s(y0), z1))
S tuples:
   FROM(s(s(x0))) -> c2(FROM(s(s(s(x0)))))
K tuples:
   LEN(cons(z0, z1)) -> c6(LEN(z1))
   FST(s(s(y0)), cons(z1, cons(y1, y2))) -> c1(FST(s(y0), cons(y1, y2)))
   ADD(s(s(y0)), z1) -> c4(ADD(s(y0), z1))
Defined Rule Symbols:none

Defined Pair Symbols:   LEN_1, FST_2, FROM_1, ADD_2

Compound Symbols:   c6_1, c1_1, c2_1, c4_1


----------------------------------------

(55) CdtForwardInstantiationProof (BOTH BOUNDS(ID, ID))
Use forward instantiation to replace LEN(cons(z0, z1)) -> c6(LEN(z1)) by 
   LEN(cons(z0, cons(y0, y1))) -> c6(LEN(cons(y0, y1)))

----------------------------------------

(56)
Obligation:
Complexity Dependency Tuples Problem

Rules:none
Tuples:
   FST(s(s(y0)), cons(z1, cons(y1, y2))) -> c1(FST(s(y0), cons(y1, y2)))
   FROM(s(s(x0))) -> c2(FROM(s(s(s(x0)))))
   ADD(s(s(y0)), z1) -> c4(ADD(s(y0), z1))
   LEN(cons(z0, cons(y0, y1))) -> c6(LEN(cons(y0, y1)))
S tuples:
   FROM(s(s(x0))) -> c2(FROM(s(s(s(x0)))))
K tuples:
   FST(s(s(y0)), cons(z1, cons(y1, y2))) -> c1(FST(s(y0), cons(y1, y2)))
   ADD(s(s(y0)), z1) -> c4(ADD(s(y0), z1))
   LEN(cons(z0, cons(y0, y1))) -> c6(LEN(cons(y0, y1)))
Defined Rule Symbols:none

Defined Pair Symbols:   FST_2, FROM_1, ADD_2, LEN_1

Compound Symbols:   c1_1, c2_1, c4_1, c6_1


----------------------------------------

(57) CdtForwardInstantiationProof (BOTH BOUNDS(ID, ID))
Use forward instantiation to replace FST(s(s(y0)), cons(z1, cons(y1, y2))) -> c1(FST(s(y0), cons(y1, y2))) by 
   FST(s(s(s(y0))), cons(z1, cons(z2, cons(y2, y3)))) -> c1(FST(s(s(y0)), cons(z2, cons(y2, y3))))

----------------------------------------

(58)
Obligation:
Complexity Dependency Tuples Problem

Rules:none
Tuples:
   FROM(s(s(x0))) -> c2(FROM(s(s(s(x0)))))
   ADD(s(s(y0)), z1) -> c4(ADD(s(y0), z1))
   LEN(cons(z0, cons(y0, y1))) -> c6(LEN(cons(y0, y1)))
   FST(s(s(s(y0))), cons(z1, cons(z2, cons(y2, y3)))) -> c1(FST(s(s(y0)), cons(z2, cons(y2, y3))))
S tuples:
   FROM(s(s(x0))) -> c2(FROM(s(s(s(x0)))))
K tuples:
   ADD(s(s(y0)), z1) -> c4(ADD(s(y0), z1))
   LEN(cons(z0, cons(y0, y1))) -> c6(LEN(cons(y0, y1)))
   FST(s(s(s(y0))), cons(z1, cons(z2, cons(y2, y3)))) -> c1(FST(s(s(y0)), cons(z2, cons(y2, y3))))
Defined Rule Symbols:none

Defined Pair Symbols:   FROM_1, ADD_2, LEN_1, FST_2

Compound Symbols:   c2_1, c4_1, c6_1, c1_1


----------------------------------------

(59) CdtForwardInstantiationProof (BOTH BOUNDS(ID, ID))
Use forward instantiation to replace ADD(s(s(y0)), z1) -> c4(ADD(s(y0), z1)) by 
   ADD(s(s(s(y0))), z1) -> c4(ADD(s(s(y0)), z1))

----------------------------------------

(60)
Obligation:
Complexity Dependency Tuples Problem

Rules:none
Tuples:
   FROM(s(s(x0))) -> c2(FROM(s(s(s(x0)))))
   LEN(cons(z0, cons(y0, y1))) -> c6(LEN(cons(y0, y1)))
   FST(s(s(s(y0))), cons(z1, cons(z2, cons(y2, y3)))) -> c1(FST(s(s(y0)), cons(z2, cons(y2, y3))))
   ADD(s(s(s(y0))), z1) -> c4(ADD(s(s(y0)), z1))
S tuples:
   FROM(s(s(x0))) -> c2(FROM(s(s(s(x0)))))
K tuples:
   LEN(cons(z0, cons(y0, y1))) -> c6(LEN(cons(y0, y1)))
   FST(s(s(s(y0))), cons(z1, cons(z2, cons(y2, y3)))) -> c1(FST(s(s(y0)), cons(z2, cons(y2, y3))))
   ADD(s(s(s(y0))), z1) -> c4(ADD(s(s(y0)), z1))
Defined Rule Symbols:none

Defined Pair Symbols:   FROM_1, LEN_1, FST_2, ADD_2

Compound Symbols:   c2_1, c6_1, c1_1, c4_1


----------------------------------------

(61) CdtForwardInstantiationProof (BOTH BOUNDS(ID, ID))
Use forward instantiation to replace LEN(cons(z0, cons(y0, y1))) -> c6(LEN(cons(y0, y1))) by 
   LEN(cons(z0, cons(z1, cons(y1, y2)))) -> c6(LEN(cons(z1, cons(y1, y2))))

----------------------------------------

(62)
Obligation:
Complexity Dependency Tuples Problem

Rules:none
Tuples:
   FROM(s(s(x0))) -> c2(FROM(s(s(s(x0)))))
   FST(s(s(s(y0))), cons(z1, cons(z2, cons(y2, y3)))) -> c1(FST(s(s(y0)), cons(z2, cons(y2, y3))))
   ADD(s(s(s(y0))), z1) -> c4(ADD(s(s(y0)), z1))
   LEN(cons(z0, cons(z1, cons(y1, y2)))) -> c6(LEN(cons(z1, cons(y1, y2))))
S tuples:
   FROM(s(s(x0))) -> c2(FROM(s(s(s(x0)))))
K tuples:
   FST(s(s(s(y0))), cons(z1, cons(z2, cons(y2, y3)))) -> c1(FST(s(s(y0)), cons(z2, cons(y2, y3))))
   ADD(s(s(s(y0))), z1) -> c4(ADD(s(s(y0)), z1))
   LEN(cons(z0, cons(z1, cons(y1, y2)))) -> c6(LEN(cons(z1, cons(y1, y2))))
Defined Rule Symbols:none

Defined Pair Symbols:   FROM_1, FST_2, ADD_2, LEN_1

Compound Symbols:   c2_1, c1_1, c4_1, c6_1